((2x^3/2y^3)/(x^2y^(-1/2)))^2

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Solution for ((2x^3/2y^3)/(x^2y^(-1/2)))^2 equation: 


D( x )

x^2*y^(-1/2) = 0

x^2*y^(-1/2) = 0

x^2*y^(-1/2) = 0

x^2*y^(-1/2) = 0 // : y^(-1/2)

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

((((2*x^3)/2)*y^3)/(x^2*y^(-1/2)))^2 = 0

x^2*y^7 = 0 // : y^7

x^2 = 0

x = 0

x in { 0} 

x belongs to the empty set

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